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ℒ-1[F(s)G(s)]=∫0tf(x)g(t-x)dx , where ℒ-1[F(s)]=f(t) and ℒ-1[G(s)]=g(t) . For a suitably defined domain of s, find the inverse Laplace transform of s(s2+9)2 , from the following options: t2sin(3t) t6sin(3t)-112cos(3t) 16(1-cos(6t)) t9sin(3t)None of these!I don't know!
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Christine may have made a mistake.Please input the line number where the mistake is, or input 0 if there is no mistake.Please input the your confidence about the answer according to the following scale:1=I am very unsure2=I am not quite sure3=I am absolutely sureSOLUTION The equation of motion is obtained as line 1 ... x′′+20x′+100x=0Taking the Laplace transform: ℒ[x′′]+20ℒ[x′]+100ℒ[x]=0 Writing ℒ[x]=x¯line 2 ... s2x¯-sx(0)-x′(0)+20(sx¯-x(0))+100x¯=0line 3 ... x¯=11s+10+110(s+10)2Taking the Laplace inverse:line 4 ... x=11e10t+110te10tThe error is in line ............. The level of my confidence is.............
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Don't forget to put negative sign if your answer is negative integer.
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